# 도시 분할 계획 - BOJ
- union-find 및 크루스칼 알고리즘 활용하여 풀이
def find(parent, x):
if parent[x] != x:
parent[x] = find(parent, parent[x])
return parent[x]
def union(parent, a, b):
a = find(parent, a)
b = find(parent, b)
if a < b:
parent[b] = a
else:
parent[a] = b
N, M = map(int, input().split())
parent = [0] * (N + 1)
edges = []
ret = 0
for i in range(1, N + 1):
parent[i] = i
for _ in range(M):
A, B, C = map(int, input().split())
edges.append((C, A, B))
edges.sort()
biggest = 0
for edge in edges:
C, A, B = edge
if find(parent, A) != find(parent, B):
union(parent, A, B)
ret += C
biggest = C
print(ret - biggest)